Crash Streak Probability Calculator

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This calculator tells you how often a run of early crashes should happen in a fair game. Enter the house edge, the multiplier you count as an early crash, and the length of the run. It returns the chance of that streak, how many rounds you can expect between streaks, and how many you should see in a 200-round session. It is for anyone who has watched five crashes under 2x in a row and wondered.

Crash Streak Probability Calculator

Think that run of early crashes was rigged? Set the threshold and streak length below and watch how routine it actually is. No manipulation needed.

House edge
3%
Aviator = 3%
Crashed below this multiplier e.g. 2.00 means every round crashed before reaching 2x
How many times in a row?
5
Consecutive crashes below your threshold
Probability of this streak
--

Consecutive crashesProbabilityRoughly once every

Each crash round is independent, so probabilities multiply. The "once every" and per-session figures count a run of that length or longer as one streak, the way you would see it on screen.

🔢 How to read the results

Start with the single-round figure. At a 3% edge, a round crashes below 2x 51.5% of the time. That is the most common misreading in crash games: players assume a 2x cash-out is a coin flip in their favour, when it is slightly against them. The streak probability is that number multiplied by itself for each round in the run, and the tool converts it to a plain frequency: once in so many rounds.

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The table below the inputs runs the same calculation for every streak length from 2 to 15, and the last panel counts how many runs of your chosen length or longer to expect in 200 rounds, which is roughly 80 minutes of Aviator play. If that number is above one, the streak you saw is not a signal. It is the normal output of a fair random draw.

💡 Key insight

In a 200-round session at a 2x threshold and 3% edge, expect three or four runs of five or more straight crashes under 2x, about two runs of six or more, and about one run of eight or more every two sessions. Screenshots of these runs are the main evidence offered in every thread asking whether Aviator is rigged, and every one of them is the expected output of a fair game.

📊 The maths behind it

The chance that one round crashes below a multiplier m is 1 − (1 − edge)/m, because (1 − edge)/m is the chance of reaching m. Call that p. Rounds are independent, so the chance of n early crashes in a row is p multiplied by itself n times, written p^n. A longer run counts as one streak, not several. So a run of seven early crashes is one streak of five or more, not three. Counted this way, a streak of n or more turns up about once every 1 / ((1 − p) × p^n) rounds. The extra (1 − p) is there because a new streak needs a round just before it that did not crash early. In a session of N rounds you should expect about p^n × (1 + (N − n) × (1 − p)) of them.

Worked example at 3% edge and a 2x threshold, where p = 51.5%:

In a rowProbabilityOnce everyExpected in 200 rounds
226.5%7.8 rounds25.7
313.7%15.1 rounds13.2
53.6%57 rounds3.5
80.49%417 rounds0.47
100.13%1,571 rounds0.12
150.0048%43,000 rounds0.004

Lower the threshold to 1.5x and p drops to 35.3%, so five in a row becomes a 0.55% event, about once in 280 rounds. Raise the edge and every figure moves the other way. The tool recomputes the whole table when either input changes.

🎯 What it cannot tell you

It cannot prove any specific game is fair. It can only show that the streak you saw is consistent with fairness, which is a different claim. The test of whether a particular round was fixed in advance is a hash check, which the provably fair verifier performs and the verification guide explains step by step.

It also says nothing about the next round. After five crashes under 2x, the chance of a sixth is still p. There is no pressure building and no correction coming, and every product sold on the promise that there is belongs in the patterns article or the scams guide.

The bottom line: Runs of early crashes are routine. At a 2x threshold you will see a five-streak two or three times an hour and an eight-streak about once every three hours. If a run makes you want to bet bigger because a high round is due, close the game: that feeling is the most expensive thing in crash gambling.

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❓ Frequently asked questions

Is a streak of early crashes proof of rigging?

No. At a 3% edge and a 2x threshold, a run of five or more happens about once every 57 rounds and a run of ten or more about once every 1,571 rounds. A busy game runs thousands of rounds a day, so every streak length up to about 15 is seen regularly across the player base. Rigging would show up as a persistent gap between the observed and expected frequencies, not as a single run.

After five early crashes, is a high multiplier due?

No. Each round is generated independently from its own seed. The chance of the next round crashing below 2x is 51.5% whether the previous five crashed at 1.01x or 100x. Betting bigger because a big round feels due is the behaviour the edge is built to profit from.

What threshold should I use?

Use your own cash-out target. If you cash out at 1.5x, a crash below 1.5x is what costs you money, and p is 35.3% at a 3% edge. If you cash out at 3x, p is 67.7% and long losing runs are far more common.

The calculator says a 15-streak is rare, but I have seen one. Why?

Rare per starting point is not rare per player base. A 15-streak at 2x occurs about once in 43,000 rounds. A game running 150 rounds an hour produces about 3,600 rounds a day, so any single game shows one roughly every 12 days, and there are hundreds of games and operators. The screenshot travels further than the 42,999 rounds that did not.

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